05-09-2017, 04:23 AM
(This post was last modified: 05-09-2017, 06:02 AM by Ancient Vizier.)

Memoirs of a Pi Jedi

Chapter Six

Geodesy? We got lots of that!

I seem to remember the subject coming up of a different value for the remen that my favorite one. To be fair, I have been forced to conceed diversification (the "Thoth Remen") and there may be others. So I took a remen of 12 / Pi^2 and fed it too into the Cubit-o-Matic 2000 ((360/ Remen x) = cubit y x cubit z)).

I noticed it seems a little strange I am calling 1.721325932 a Thoth Cubit when a theoretical cubit of 33.33333333 / 19.46773764 = 1.7122345672 has a little bit of Thoth in it too...

If I put my favorite cubit in the Cubit-o-Matic 2000 and input 1.7122345672 as a candidate, I get back as its pair a figure of 1.728000000, which I thought was intriguing.

If I put the 12 / Pi^2 remen into the Cubit-o-Matic 2000 and input 1.7122345672 as a candidate, I get back as its pair a figure of 1.729249823, which I thought was even more intriguing. You might say that's an old friend of mine. I've never hauled off and called it a cubit in the past, but it's a rather interesting number.

Where have I seen it before? Silbury Hill (the terrestrial counterpart of Cydonia's "Tholus" in David Percy's reckoning - his concept of some of Silbury plain's monuments as a model of Cydonia sans Face is probably the reason I ever bought a Hoagland video in the first place). In a model I made of Silbury, there was something fairly remarkable in the way it pulls off an approximated trigonometric function that I still think is really cool.

Here's a post from my initial exploration of Silbury's proportions. Please pardon any Munck Junk not weeded out. I'm not going to censor his name at every turn here, sorry.

excerpt from:

"Ah found mah three-ills... on Silbury Hill..."

Thu Feb 20, 2003

Grid Point msg. board

For sure I should be wearing one of those "Don't Follow Me, I'm Lost" bumperstickers... thing about being lost, sometimes you think you were in a great place until you figure out you were lost... and you can even make up your own names for the territory, like "Indeterminant Geometry", but that really doesn't have a lot of inherent ability to change the fact that you're lost, if that's where you actually are...

Silbury Hill... would like to have more data on this. I'm the guy who decided it was a bright idea to re-write all of Carl Munck's model on Stonehenge, Silbury, and Avebury into "WGS 84 datum", I almost feel personally responsible for making sure that the "WGS 84" is satisfactory in every last detail... one of the troubles being that I've never actually seen a model of any of these three in every last detail... although at this second I have virtually every Carl Munck product in existence in my possession...

Another problem being the question of who has the Silbury data to begin with... I have a shelf starting to brim with works on Stonehenge and Stone Circles, that don't actually even begin to represent British archaeology, but alas, poor Silbury, mightiest monument in the Isles it may be, does not happen to actually be a Stone Circle... I'm sure we're all dying to know how it answers the Megalithic Yard, but Thom's indices don't even give it honorable mention...

Carl Munck, "Whispers from Time, Vol II", p 273...

Silbury: Diameter, 550 feet; Area: 237582.94 feet

Grave Creek Mound: Diameter 317.542 feet, Area 79194.3 feet

(79194.3 x 3 = 237582.94)

All of which, along with Munck's figures for Silbury, are predicted on a slope angle of 30*...

Carl Munck, "Aquarius", No. 9, pg. 5

"Its flattened upper circle has a diameter of 100 feet" (Circumference= 100 Pi)

Aside from Munck's Grid Values, 67858.40132 / 2662.867199 = 2.5483208098... although I have a model of how he got those figures... That's really all the data I have...

Now, I'm sure I'm likely to get us all into trouble trying to steer the boat through long-charted waters myself... but should we just give up there...? Hmmm... where would we all be, if "give up" were in our vocubulary?

Seriously, there are two things I commend, one of them is when Carl Munck does not even want to touch a monument because he doesn't have enough physical data, and the other is when someone is not going to let a lack of physical data be an obstacle. There are cases out there where we may never get that physical data, and I refuse to accept that it means even the Grid Values of those monuments are irretrievably lost. Quite the contrary, I like to think the Matrix means that even if there's nothing left of a monument but an unmeasurable crop stain, the ancient voices haven't been silenced...

Okay, let's look at what Carl Munck has here: Diameter 550

D / 2 = R, R^2 x Pi = Area, so... (550 / 2)^2 x Pi = 237582.9444

Carl Munck, "Whispers from Time, Vol II", p 273...

Silbury: Diameter, 550 feet; Area: 237582.94 feet

So... we know his figure for area is based on 550 feet EXACTLY, and we know the formula is for the area of the Base that Silbury rests on, not all of Silbury's exposed surface...

I've said this before, and I've been trying to put it to the test lately... 550 is NOT in the Matrix as far as I've been informed... but I know two figures that are very close... one of them is 550.4373139, exactly 1/100 of Carl Munck's Grid Latitude for Monk's Mound at Cahokia..

What could you think if Silbury had a Diameter of 550.4373139 feet?

Interesting thing, Silbury is stone underneath... we've known that for a long time... we know that it's a very bizarre looking structure, split into radial divisions into an octagon or nonagon (archaeologists do not sound sure which yet for some reason). My guess is that it's a nonagon, nine sides, and 9 Radians = 515.6620156, which is 1/100th of my Grid Longitude for Silbury... now I'm not in favor of basing any values on anything that was had to be discovered by invasion of a monument, there are other ways... in fact, that's another one I got from Carl Munck's new publications, and that is the partnership of the Area of a Circle and the Surface Area of a Hemisphere...

No, it's not really a strange case where addition works well for the Matrix, it's really multiplication...

The Surface Area of a Hemisphere is 4 times the Area of a Circle, so adding the two really means 5 times the Area of A Circle... Area of a Circle 10313.24031 x 5 = 51566.20125...

Maybe right there is where we are warned that maybe we shouldn't take this "Cone" stuff too seriously... ?

Anyway, say we have a Silbury with a Diameter that's a decimal harmonic of the Grid Latitude of Monk's Mound... they're different forms, of course... Silbury is something in the circular family, Monk's Mound is a more rectangular species... so what have they got in common besides just being "major monuments"?

Well, it's too late to predict it now, but speaking of monument invasion, guess what they found at Monk's Mound underneath? Who'd have guessed, but just like Silbury underneath, stone...

Maybe it's more to the point here that 550.4373139 seems to belong to the British Landscape as well...

Proposed Diameter Silbury 550.4373139 x WGS 84 Grid Point Silbury Reciprocal of the Squared Yoda Meg Yard, RSYMY 1.351926225 = 744.15060399, decimal harmonic of our customary Area of Stonehenge, one of those Carl Munck figures I wouldn't waste a second arguing with, and good luck to anyone who cares to... That's just an example...

I have considered 550.0394833 feet... not off my much... in fact, over at the Celtic New Zealand site, they suspect this although they can't figure it out and I'm not surprised...

550.0394833 feet x Pi = Circumference 1728.0 isn't that cool? CNZ thinks it's 1728.0...

(God, they're brilliant, I just wish they'd wake up and smell the Pyramid Matrix)

One problem is that 550.4373139 x Pi seems to belong even more to the British Pyramid Matrix than does 1728.0... in spite of 1728.0 having at least several very glowing items marked on its resume...

550.4373139 x Pi = 1729.249822

And this "affinity" of 1729.249822 over 1728 includes something very important in context, which is the ability to resonate with Silbury's own (WGS 84) figures...

They're not necessarily the most obvious, but 1729.249822 is in the middle of a run of responses to at least 5 powers worth of 1.351926225, the Reciprocal of the Squared Yoda Meg Yard, RSYMY the "WGS 84" Grid Point of Silbury...

There's also this: 51556.20156 / 1729.249822 = .0298199833

That IS a decimal harmonic of what is so far the most recognizable figure for approximated WGS 84 reciprocal flattening... which is probably even more "navigational", to borrow CNZ's phrase, than is 1728...

1729.249822 is also "navigational" in the sense that 1729.249822 x 4 = 6916.999288, which is a decimal harmonic of the "miles-per-degree-of-equatorial-longitude" figure associated with 24901.19742 miles, which is a Matrix Valid figure obtained by cubing the WGS 84 Stonehenge Grid Point, that comes within one mile of the "almanac" figure for the Earth's equatorial circumference, and answers the Apex latitude at Giza in a substituted Munck equation, addressing the Michael L. Morton Apex latitude value for the Great Pyramid, which also addresses the Grid Latitude of the D & M Pyramid on Mars...

24901.19742 / 360 seconds = 69.16999284 miles per degree / 60 minutes = 1.5283321 miles per minute / 60 seconds = .0192138869 miles per second, .0192138869 being a decimal harmonic of 19.4677376 x Pi^2...

----------------------------------------------------------------

And that's the way it was.

(note on: 1.5283321 miles per minute...should read 1.152828584 = dh perimeter of inscribed circle on face of Yoda model pyramid in feet, more geo-modelling?)

The way it is, is that I'm incredibly tempted to just haul off and declare 1.729249823 a "Geodetic Cubit".

Another way of saying the above is that 24901.19742 / 144 = 172.9249821, allowing a Silbury Hill a base perimeter to serve as a scale model of the earth using a ratio involving modern feet and miles.

On a vaguely related note, I was going over that academic article on the cubit

https://www.hindawi.com/journals/janthro/2014/489757

Table 2 has some "Hebrew Linear Measures"

https://www.hindawi.com/journals/janthro...89757/tab2

After some deliberation, I decided that the best way to interpret a "Span" of "8.745" inches might well be as = 8.760481938 inches. (I get decimal harmonics of 8.760481938 into my calculator by remembering that 45 x 19.46773764 = 8760.481938)

That gives a value of 8.760481938 inches / 12 = .7300401615 feet (a remen fraction), which is one of two values vying for identification with the Egyptian Small Span along with a Squared Yoda Meg Yard fraction.

Of the measures stated by source, a common scale cubit of 17.49 in / common scale span of 8.745 = 2.

Accordingly, the corresponding cubit = 8.760481938 inches x 2 = 17.52096388 inches, or 1.460080323 ft.

1.460080323 x 2 = 2.920160646 = (cube root 24901.19742) / 10

17.52096388 x Pi = 55.04373141 proposed diameter Silbury Hill / 10

17.52096388 x Pi^2 = 172.9249922 proposed base circumference Silbury Hill / 10

When we observe that our basic concept of Silbury essentially has a circular base and exercise the prerogative to throw icons of circular mathematics at it, such as 360, the radian 57.29577951 or Pi

1729.249822 ft / 360 = 4.803471728 = Yoda Ht. Great Pyramid / 100

1729.249822 ft / 57.29577951 = 30.18110298 Yoda Perimeter Great Pyramid / 100

It's rather suggestive that there may be geodetic concerns built into that model of the Great Pyramid that may not have received sufficient focus before.

24901.19742 / 480.3471728 ft Yoda Ht. GP = 51.84, as in 51.84* Great Pyramid angle

24901.19742 / 55.04373141 proposed diameter Silbury Hill / 10 = 452.3893421 ft proposed height Great Pyramid with paving but without pyramidion, and

24901.19742 / (55.04373141^2) = 452.3893421 / 55.04373141 = 8.218725921, or 1 / one-tenth of my favorite remen of 1.216733603 feet

I thought that was pretty good for just being me copping a whiny attitude that "550 isn't in the 'Pyramid Matrix'"

"Work and pray, live on hay, you'll get Pie In The Sky when you die." - Joe Hill, "The Preacher and the Slave" 1911