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Stargate Pentad Pleiades Heliospheric Time Pyramid
#1
My computer won't even open a pdf right now,
so I do not know wether or not the link works yet.
well here it is,
and the summation of the work as a preliminary introduction,
and of course for now this is all Copyright V. Showell 2007.

Opening the Stargate to the Pleiades,
The Pentad-12 Mounds Heliospheric and Vegisimal Calendar
[and the 707 day Mars sidereal] and
The Mayan Heliospheric Time Pyramid
http://www.keithlaney.net/TheHiddenMessage/VS3.pdf

You will have to read the document sections I specified as:
the document text to the Jupiter vegisimal extrapolation,
from there SKIP all the way past all the math and Circle of 9 to the:
Mars-Jupiter synodic Conclusion, to the Final Conclusion,
to the Final Appenix and the Final Random Time Pyramid Proof
at the end of the document,
unless you want to read all 100+pages.

As I said over in the HM magazine section,
the Mayan Heliospheric Time Pyramid is a feature
in the conclusions of my document, and it is AMAZING
that my Time Pyramid developed from the Pentad Length EA=[2]
as the [2]base and SquareRoot[2] Time Pyramid seen in the image below,
produces time functions between Mars and Jupiter
as the Pyramid SIDE FACE length sqrt[5]= [2.236],
and that is the YEARS it take Mars and Jupiter to align heliocentrically,
Image is down below but for reference:
[Image: 11sqrt1.jpg]
and the Pyramid Side ANGLE Length division below:
[2.44949] / [Base Diagonal] SqRt[2] length[1.4142],
[2.44949] / [1.4142]= ***[1.732]SqRt[3]***
AND
Sqrt. [2]= [1.4142].../ Sqrt [3] =[1.732]
.................[1.4142] / [1.732] =.........***[.8165]***
The synodic of Mars and Jupiter is.......[816.5] days,
all in a Pyramid developed from the Pentad tetrahedral grid pattern.

This post is to draw interest to my all too long document
as a "proof " using some "Heliospheric Time Pyramid" derivations
of the Pentad numerations which exhibit
the square roots of [2], [3], [6,] [2x sqrt3],
and the Pentad mounds EA length of [2] units,
shown in the image supplied below,
and why the square root of [2] was discussed at length
by the SPSR document on the Pentad-12 mounds.

***The most important number on Mars***
comes from the angles in the Pentad-12 mounds that predominate.
In the SPSR study these were
[19.5] , [26.5] , [18] and [30] degrees.

That most important number for Mars is [26.5] degree angles.
The [19.5] fits very well on Mars also,
but it also functions on all the inner planets primarily.

The [26.5] degree angle works with Mars and Earth
specfically in a numeric set relationship that creates the
[53/52]{52/53} function, specifically with the newly proposed 707 day sidereal,
{and the Mayan 702 day calculative sidereal},
for Mars seen in most recent scientific publications,
{See document text and below}

The Pentad may also symbolize the first 5 planets.
If so, there may be one mound that is much bigger than the rest,
to represent Jupiter.
------------------------------------------------------------------------------------

I use "coincidental numeric set" searches in Pentad nukerations
to decipher the Omkulkan Codex of the 12 Mounds several angles.
I explain how "numeric sets" are independant of decimal function,
in the beginning of my document at length.
.[780,000] is 1000 synodics,
and this is still [780] as a numeric set, or specifically [78].
[3] is {.03] , [.3] , [3] . [30] , [300]and so on,
it is different than [.o33333] , [.33333]. [3.33333] [33.33333],
[19.5] is the numeric set [195], etc.

NOW back to EA earlier in the 19.5 thread,
and his attribution of [33] to the radius of Mars,
and the huge debate over this attribution earlier in this thread
and whole argument that [33] or [33.33333] does not equal [34],
as in [34] correlates to [3397] Mars radius....and this is why:
No one has done this:
Take the Equatorial radius [3397]...which is actually [3397.45]
and I will show you why here next:
[3397] is numeric set [3397] so place the decimal anywhere within it as in:
[.3397] x 780 day Mars synodic =[264.96]=.....[265]
AND THERE is your [26.5] degree angles correlation in the mounds!!!
Seeing how close this [264.96]=.....[265] is, I decided to wrench out
the actual EXACT figure to attain the exact [265],
that is [3397.45] for the radius of Mars, less than half a kilometer diff.
[.339745] x 780M =.....[265]
NOW Use the Heliospheric [13] Key on the Mars sidereal of [687] days
and the original derivation I performed on the Pentad-12 mounds,
which procured the [5], [12] , [13], as a calendric function,
[5 x 12] = 60 minutes,
[13]x{60} =780M={65}x[12]
....and [5] x[156]=780M
..................[156]={12 x 13}
and apply that to the [687] day Mars sidereal:

[13] x [53]=[689]
[12] x [53]=[636.....and the Big Kahuna Pentad [5]next
[5] x [53]=[265]AND THERE is also your [26.5] degree Angle
........[53]=[26.5] x [2]
So from this one sees that pentad[5] x [53] =[265]

Now by curious chance the Mayan Tzolkin religious calendar is
[13] x [20] = [260] days.....Cheers




SPECIAL NOTE

EDIT IS AT BEGINNING
A multiplication sign was erroneously installed
instead of a division sign
in this equation
Sqrt. [2]= [1.4142].../ Sqrt [3] =[1.732]
.................[1.4142] / [1.732] =.........***[.8165]***
The synodic of Mars and Jupiter is.......[816.5] days,
all in a Pyramid developed from the Pentad tetrahedral grid pattern.
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#2
Yes, your PDF file opens successfully. That's about all I'm capable of analyzing right now. <img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
Don't believe anything they say. <br />And at the same time, <br />Don't believe that they say anything without a reason. <br />---Immanuel Kant
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#3
Is there some new drug I ain't heard of, called mathamphetamine? I think I might need it to follow all that.
<img src="{SMILIES_PATH}/stars.gif" alt="Stars" title="stars" />
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#4
It's simple really, despite the math.
Vianova's saying the Cydonian mounds represent a hyper calendar, and quite a grand one too

<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
On a satellite I ride. Nothing down below can hide.
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#5
Incredible V Cheers



forgive my mising ss's ...crumbs
&quot;The impure can become pure through the process of elimination, <br />but error can never be transformed into truth.&quot; <br /> Schwaller De Lubicz
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#6
Quote:It's simple really, despite the math.
Vianova's saying the Cydonian mounds represent a hyper calendar, and quite a grand one too

<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
That's very cool.
I can see why things like that get debunked and swept under the rug, too. It's so threatening to people's belief systems.
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#7
<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
Never invite a Yoda to a frog leg dinner.
Go ahead invite Yoda to a Frog leg dinner
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#8
Quote:Incredible V Cheers

Sorry I haven't responded,
needed a night off,
and today went up to Mt Baker
and God smiled upon the mountain bhagwan,
and gave him 12 pounds of King Boletes,
in AUGUST!!!!
and I have been in the kitchen tonite cleaning them for 2 hours
and making a huge porcini patsa suace out of them,
and etc.

OK to answer,

".....I'm presuming this calendar has a far higher degree of accuracy
than even the mayan calendric system....
Be interesting to compare it with that (Mayan) calendar
which has a couple of proposed timelines..."

No I think the Mayans were right on the money.
My guess is that they knew of the unique 707 day sidereal,
and the planetary alignments that most likely go with it,
and accounted for it also for the purposes of agricultural planting,
water tables, and for religious reasons.
Religious reasons?
Even though the Olmec had a Quetzalcoatl counterpart
1500 years earlier tha the mayans,
as seen in Monument 19 La Venta,
and shown in my document as Omkulkancoatl,
the Mayans nonetheless had him as a "God".

My guess is that the Mayans were aware of
planetary celestial uniquities and conjunctions etc,
which also connected to the Pleiades.
They have an implied usage of the '13 heliosphere calendar"
in their maths,
and if there was an actual culture on Mars,
these "peoples" did as well,
as the 26.5 degeree angles would attest to,
in my math correlatiions.

the key is my pyramidal calendric emanating from the pentad,
which displays all the square roots and more.
I have not dissected that Pentad EA=[2] baseline pyramid fully yet,
and I am sure that the [12] will be in there as well,
seeing how the square root of 5 was the Side Face length
corresponding directly to the alignments of Mars and Jupiter
every 2.236 years.

So let's try it now,
before i go bedbugbye.

If you look in the image with the Pentad as EA length[2]
http://i176.photobucket.com/albums/w174/...1sqrt2.jpg

and all the various square roots
you see the [2Sqrt3] which is{2 x Sqrt[3]}
BUT it also is the Sqrt of [12]
which is a much better way of looking at it,
and I need to find that in my pyramid.

Now back to my PentadEA=[2] pyramid,
http://i176.photobucket.com/albums/w174/...1sqrt1.jpg

first look at Side Face length=SFL and...Side Angle Length=SAL
[2.3236] =SFL.....[2.44949]
Now multiply them,
[2.236] x [2.44949] = [5.47705964]...guess what that Is?
Square root of [30] and there is your [30] degree angle in the mounds.

Now the height times the SFL
[2] times [2.236]= [4.472].......that is sqrt of [20]
and there is your vegisimal base,
and [20] / by [30] above = [.666666666]

Now take the height times the SAL
[2] x [2.44949] = [4.89898]......sqrt of [24]
and that is 2 x [12],
and [20] above / [24] = [.8333333] see my document on that decimal
applied to all the synodics and sidereals

Base diagonal [1.4142] x SFL[2.236] =[3.16215]....=sqrt of [10]
Now look to the [24] above paragraph and
[10/ 24] = 5pentad/ 12 mounds

But I still want that [12] direct from the pyramid lengths
to accompany that sqrt of [5] on the pyramid side face,
WHY?
because it is Pentad[5] within [12] mounds at Cydonia,
and from the beginning with the 780M synodic
I used the [5] [12] to determine the [13] and the vegisimal calendar,
and the [12] needs to extrapolate directly from the pentad as well..
So
we have the [5], as sqrt of 5 in the SFL,
the [20] as sqrt of {height[2] times the SFL},
***and the [12]***
is the square of
the base diagonal[1.4142] x the SAL[2.44949] = [3.46406]
and sqrt of [12] is.............................................[3.4641]
same difference and the [12] is accounted for.

And if you want the [13]
take the [12] above
and multipl;y it by the [19.5 / 18] degree angles in the mounds.

Now even though I have the 5 and 12 as [5 x12] = 60 seconds,minutes
watch this,

Base diagonal length used is sqrt of 2 or [1.4142]
SFL is sqrt of [5] or ..............................[2.236]
SAL is the sqrt of [6] ............................[2.44949]
Now
multiply
the three of those above all together
[1.4142] x [2.236] x [2.44949]= .........[7.745657743]

Now square that............................... [7.745657743]sq

Ha!,..........[60]......and [13] x [60] = 780M synodic
and if you take every number on that pyramid and multiply them all
and then square that you will get [240]

<img src="{SMILIES_PATH}/hmm2.gif" alt="Hmm2" title="hmm2" />


Of even as great of connsequence is the way
i used the radius of mars in derivations.
BELIEVE ME,
the raidus of Mars is [3397.45] not just 3397]

If you go thru my math on that in my last post you will see why.
this is crucial and amzing that this works like this

[.3397] x 780M = [264.966]...close enough to [265] anyways
[.339745] x 780M = [265]

[13] x [53] = 689M sidereal
and Pentad [5] x [53] = [265]
and [2 x 26.5] = [53]

Now there was one I left out using the radius of Mars application
the one to earth.
First I got this fantastic result using the equation:

{Equatorial radius of Mars decimalized} =[X]
[synodic or sidereal of planets]= [Y]
****So [X] x [Y] / [26.5]degree angle= [Z]***

This equation using the premier Mayan functional numbers on Mars,
the 702M Mayan calculative sidereal,
and the 780M synodic to Earth,
yielded this amazing result.

[.339745] x 780M / [26.5]= [10]
[.339745] x 702M / [26.5]= [9]
AND [9] x [78]= 702M.............[10] x [78]=780M

Now for earth
Mars radius x L.E.Y.  .........................................../ 26.5
[.339745] x Lunar Earth Year [364] = [123.66718] / [26.5] = [4.666686]

[4.666686]...? ...dunno, but if you do this,

[.4666686] x 780M synodic = [364] lunar year.....Ha!

Also the 936 of the Nine,
since [10 x 78=780M] aned [12 x 78= 936]

[.339745] x [936] = [318] / [26.5] = [12].......x 78= 936

so what does it all mean?
It means that the Pentad as structured reveals not only
unique geometry and a "Codex of Angles"
but it also expands into the perfect pyramid that expresses time
through all the planets,
and
THAT IS NOT Coincidence and Chance.

My PentadEA length=[2] base and height Time Pyramid
proves that, along with everything else.

The 707 day Mars sidereal IMO occurs in a "heliospheric resonance"
of planetary alignments and/or conjuctions,
and this opens the "planetgate" from Earth to Mars,
and to the Pleiades simultaneously,
and there is a "NATURAL STARGATE"
to the Pleiades initiated by the planetary alignments
with the power of Jupiter,
a wormhole?
a conduit of instantaneous flashpoint travel vector,
from the Pleiades here,
and it isn't a little "tmeless tunnel",
you can move possibly planets and definitely moons through it,
not to mention the mother ship moon.... .

".......and the God Iapetus came to visit his daugher Iapetusitep,
at the Dance of the Timelords at the Olympus Mons Temples,
in the celebration of the opening of the Stargate,
and the planetary pyramidal conjunction
that resonated the stargate vector........." 

Yes a lot of wild conjecture,
but then I gotta strong feeling on that one with the Pleiades.


I think that "Pentad" style "geologic" formations
need to be looked for here on Earth.
We look for too small of criteria,
time to look at "sets" of land formations,
....but they may be underwater....now...dunno

my guess is that far more lies under the sands of the sahara
than we might think.
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#9
Hi Via Worship
Reply
#10
I read as much of the pdf as I could understand. Not understand, but at least read the parts that weren't mathematical formulae.

One more question - I had seen your ideas about the "spice bags" on another thread. I am curious where you found a reference to spice bags, or is this your own original idea about what these bags are?
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#11
Hi,
a quick shot at this for you QO,

at the beginning of my document are two links
that "propose" the 707 day Mars sidereal from their evidence.

The 707 day sidereal produced the magnificent
synodic between Mars and jupiter,
of 845 days.
This is directly proportinal to the [13] ancient heliosphere calendar
like this with the 780M day synodic to earth:

12 x 65 =780M
13 x 65= 845MJ
now
780M/ 845MJ = 12/13 AND the [18 / 19.5] degree angles in the mounds,
and the Pentad[5] , the [12] and the [13]
were the original factors deriving the vegisimal calendar
from the 780M synodic of Mars and Earth.
{see very beginning of my document}

Tjhe 707 day sidereal occurs in a geometric alignment of the planets
probably all five inner planets, Mercury thru Jupiter,
and has something also to do with the Earth moon phases.

My contention is that when this occurs,
the "Natural Stargate" or wormhole or whatever conduit
you want to call it,
at the very least opens from Mars to Earth,
and to the Pleiades as well.

YES,
this is a "Natural Stargate" independant of machineries
which would also create a "stargate".
This stargate is a "planetary geometric resonance"
galactically vectored to the Pleiades,
that with the power of Jupiter in the planetary alignments
opens the doorway.
And it is a BIG vector,
like I said,
one could move moons and possibly planets through it.
Look at Iapetus as possible evidence.

IF all this is true,
then the Pentad is a receiving/sending station possibly,
and there would be one on Earth
or on earth's Moon as well,
remember that hexagonal enormous landform on the moon
that Keith has shown in images?

ALL this at this point is conjecture,
except the 707 day sidereal producing the geometric alignment,
that is for certain somehow,
and that appears to be proven in the Time Pyramids.

Now remember my
"Omkulkan Codex" with the mounds angles.

you just start manipulating the angles mathematically,
by adding , subtracting , dividing , multiplying,etc

Now one does the same with my earlier above post Pentad Time pyramid
of the Pentad lengthEA= [2] as the pyramid base and height,
which gave us time functions of Jupiter.

So watch closely,
as I will use the Side angle , Side face and diagonal lengths etc
from that Pentad Time Pyramid to produce further results 
by "Codexing"

remember the abbreviations
SFL = Side face length= [2.236]............sqrt of [5]
SAL = Side Angle length = [2.44949].....sqrt of [6]
BDL=Base diagonal length = [1.4142] .....sqrt of [2]
BH= Base and height= [2]

If you remember I took the radius of Mars as a decimal
and applied it to various synodics and sidereals,
in the equation
[.339745] x [X] / [26.5] degree angle = [Z]
and for this proof I will use the Venus synodic to Earth

This went as such:
[.339745] x 585Vsynodic / [26.5] =.............................. [7.5]

Now
from the Pentad Time Pyramid
SFL / BDL = [1.581106]......squared=[2.5]
SAL / BDL = [1.732]...........squared = [3]
Now multiply the two products,
[1.581106] x [1.732] = [2.738475592]...now square that...= [7.5]
or simply [2.5] x [3] = [7.5]

SO
using the radius of Mars times the Venus synod / [26.5] = [7.5]
and using the lengths in the Pentad Time Pyramid
[1.581106] x [1.732] and squaring them you get=...........[7.5]
thus
the synodic of Venus to earth is accounted for
in the PentadEA length = [2]Base and height Time Pyramid!!!

OK
a couple of other quick "Codexes"

SAL / BDL= [2.44949 / [1.4142]= [1.732]....= sqrt of [3]
Take the [3]
and multiply it by the mounds angles [26.5 / 30]degrees
[3] x [.8833333] = [2.65] on the money
and there is your "numeric set"
for the 26.5 degree angle...........Ha!

One more
SFL / BDL = [2.236 / 1.4142]= [1.581106].....now do the same function
[1.581106] x [26.5 / 30] degree angles
[1.581106] x [.8833333] = [1.396643581]....now square that
[1.396643581] squared = [1.9506].....or just...... [1.95]
and there is a correlation numeric set wise
to the [19.5] degree angles in the mounds

one more real good one

BDL= [1.4142] / Pentad Pyramid base[2] = [.7071]
.....and there is the 707 day sidereal "numeric set"
NOW
BDL=[1.4142] / SAL=[2.44948]
[1.4142] / 2.44949] = ..................[.577344672]
NOW CODEX THAT
with the 707 day sidereal decimal

[.7071] x [.577344672] = [.408182683].....now square that
[.408182683] squared =...... [.1666]

Now where was [numeric set [1666] seen before?

Divide the 30 degree angle by the 18 degree angle in the mounds

30 / 18 =......................... [1.66666]

That is what i mean by "Codexing"
and that decimal variations do not matter,
they are distinctly correlative as "numeric sets"

Hope that got explained properly.

For refernce above here is the Pentad time Pyramid again,
with the "lenghts "...SAL, SFL, BDL etc

[IMG]http://i176.photobucket.com/albums/w174/elvis-boletus/11sqrt1.jpg[IMG]
Reply
#12
For above post the refernce did not post
[Image: 11sqrt1.jpg]

Oh yes I forgot this for the END of the above post!!!
in above post the numeric set [1666]
or the [.1666] that was from this:

BDL= [1.4142] / Pentad Pyramid base[2] = [.7071]
.....and there is the 707 day sidereal "numeric set"
NOW
BDL=[1.4142] / SAL=[2.44948]
[1.4142] / 2.44949] = ..................[.577344672]
NOW CODEX THAT
with the 707 day sidereal decimal

[.7071] x [.577344672] = [.408182683].....now square that
[.408182683] squared =...... [.1666]

that [.1666]
times the Base of the Pentad Time Pyramid [2]
[2] x [.1666] = [.33333]
and there is our [33.333] function
which gave us the synodic of Venus in the very first place
[19.5 / 33.333] = 585V synodic
Reply
#13
Wow!

Just fucking wow!

You've even got me "getting it" now Vic

what a truly intricate and omniscient cosmic connection.

Applause Applause <img src="{SMILIES_PATH}/applause.gif" alt="Applause" title="applause" />

I've forwarded this thread to all kinds of folks.
Don't sweat it if it takes 'em a while to grok, or even if it's unimportant to their scheme of things.. doesn't change the utter profundity of your discovery one bit.
On a satellite I ride. Nothing down below can hide.
Reply
#14
Victor,
I have a couple certain fairy famous and outspoken persons that are extremely interested in your discovery and have asked me to request you boil it down to a meat and bones synopsis -so they can grasp your main premises before diving into your theory.

I know, pain in the ass, and you do have it all lain out already,
and those of us who have been following this are keen on your preponderances..
but give us an introduction that makes it clear how you plan to kick everyone's head in with this knowledge
If you can prove it, say it like it is.
<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
On a satellite I ride. Nothing down below can hide.
Reply
#15
Hi Keith!
to answer your request:

to make the document concise to study,
for the interested parties,
just follow the directions I gave,

Read the preliminary text on the calendar,
through to the beginning of the
Jupiter math section on that synodic and sidereal,
then STOP,
and jump straight past everything from there,
to the Jupiter-Mars synodic and read that,
Then
GLANCE at the first few paragraphs of the Venus-Mars synodic,
then STOP,
and skip straight through
and then read the
Conclusion to Jupiter-Mars-Venus synodics,
then to the
Final Conclusion,
then to the Final Appendix,
and most imporatnt the last part of the document
The Final Random Proof...the pentad pyramid...
***then of course,
have them look at what has transpired here
in this thread.,
and/or have interested parties PM me here with specific questions
or for my phone number for a phone call session.

That is the best I can do at the moment.

First I should say this though:
All the Stargate stuff is colorful and even intuitive interpretations,
and certainly is an opinion of mine that I to a large point
believe is possible and probable,
from the evidence as I see it,
but there is no current fully derived math
to validate that premise of Stargate directly from the Pentad,
other than that the 707 day sidereal of Mars,
definitely occurs at some sort of multi-planetary
geometric pyramidal based alignment
that is distinctly important and powerful,
and historic mythologies tend to fall into place somehow
in this magnificent astro-math that the pyramidal Pentad portends.

One will have to look at the important Stars
within the "Pleiades" and ferret out alignments and conjunctions,
in relation to planetary aligments and conjunctions,
and our Moon has something to do with it.

The math stands firm as formatted Pentad calendar wise,
literally time surfing through the inner 5 planets.
The Pentad Time Pyramid stands firm,
and works as the angles in the mounds do,
by "Codexing"
in the Omkulkancoatl Codex!!
Ha!

The application of the radius of Mars to the equation as set forth,
manipulating the various synodics and sidereals,
cannot be Coincidence and Chance.
The results are too dramatic.

Like I said, the Codexing can be manipulated in many ways,
but this may just be part of a far bigger precise pattern set,
that I have not fully discovered the entire process of.
In other words
There may be distinct operational math vectors to accomplish
the "time surfing"
and I may just be stumbling on them ...or led into them...

The equation I used with the Mars radius
is definitely one of those distinct math derivational vectors.

Another one is the [52/53] or [53/52] set that is derived from
the 707 day sidereal
and the Mayan Tzolkin 260 / Mars 265 relationship
defined in my document which produces the 780M synodic
with the 707 day sidereal..

Mayan Tzolkin Earth religious calendar...[13] x [20] = [260]

[13] x [20] = [260] =pentad [5] x 52 weeks
...................[265] = pentad [5] x 53

[13] x [53] = 689 Mars sidereal
..........[53] = [2] x [26.5]degree angle

Not coincidence or chance....NASA geology wrong again.

Is there an ancient civilization that built the pentad-12 mounds?
Is it an alien Stargate base?
Or both?
How can "geology" create such a scenario
of Pentad tetrahedral grid geometry,
and then a "Pentad Time Pyramid" ?

How can the angles in the mounds "Codex" together
in synchronous symphonics,
like Omkulkancoatl on the Silver Surfboard of the Eternal Now
thru the Pleiadean cosmos?

***EXACTLY WHEN***
does the 707 Mars day sidereal occur?
and that is the Big Kahuna question of the Pentad mystery,
because 2011-12 is coming soon,
and that solar eclipse on May 20 2011,
is the return of Chicchan the Serpent,
Kukulkan the God of the Mayans,
and/or search for unusual planetary alignments
in the near future of the next 5 years.

One more "Codex" extrapolation for fun:

Earth in my document was [13] x [28] day month = [364]days
The Lunar Year.
Equation:
Mars radius x [364] / [26.5]=.....

[.339745] x [364] / [26.5] = [4.666686]

Now take the unique Mars-Jupiter synodic of [845]MJ days
derived from the [707] day sidereal.
But First.
[.339745] x [364] / [26.5] = [4.666686]

"decimal variate" the product for Earth to... [.4666686]

[.4666686] x [845]MJ = [394.334967] x [18 / 19.5] degree angles
..................................[394.334967] x [.923077]= [364]day Lunar Year

Ha!

<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
Reply
#16
&quot;The impure can become pure through the process of elimination, <br />but error can never be transformed into truth.&quot; <br /> Schwaller De Lubicz
Reply
#17
EVERYONE
BE SURE TO READ hrm's Post !!!

I am sorry hrm that I did not get to that,
I am swamped by other math applications out of nowhere,
but you obviously get the BIG picture !!!!!

Now the Biggest Kahuna of them all !!!

PLANET X

This one is even freaking ME out.
If you go to my final conclusion,
I mention a numeration that kept popping up in the derivations,
and I could not figure out why,
untill I noticed that this decimal was exactly.....one half...
of the [18 /19.5] degree angle,
and performed a profuse extrapolation of that number.

I also mentioned in my document that if Planet X exists,
it will be accounted for in the Omkulkancoatl Codex.

Don't ask me how this comes to me,
I wake up in the morning, get an idea,
pull out the calculator and Bingo.

ANGLES
[18 /19.5]= [.923076923].......this I have been rounding to [.923077]
but not this time!

So [.923076923] divided by two =[0. 4615384615]...remember that

So I took the legendary sidereal of Planet X of 3600 years,
and to get the days of the sidereal I multiplied that by
[364] day Earth Lunar Year.

[364]days  x [3600]years= [1,310,400] days....that is a lot of days,
THEN
I applied the Mars radius equation of mine to that,
[X] x [Y] / [26.5]= [Z]
where X is the Mars radius and Y is the subject synodic or sidereal.
[Mars radius decimalized] x [ Planet X ] / 26.5= [Z]

[.339745] x [1310400]= [445201.848] / [26.5]degree angle= [16800]

ALSO [1310400] Planet X sidereal / 780M=.........................[1680]
go down the list of sidereals and synodics....heh...!!!
Here is one that screams!
Take the 845M J synodic of Mars -Jupiter during the 707 day sidereal

[1310400] / 845M J= [1550.769231]....x [19.5 / 18]degree angles=
.....................................................x [1.0833333]=............[1680]

Hmm2....holy shit look back up to the top!
..........................[46.15384615]

[18 / 19.5] degree angle = [.923076923] / Pentad Pyramid EA length[2]=
.........................[.4615384615]

Now, I wonder if that is just coincidence...?

[16800]
Do I recognize it?
In passing the Vegisimal synodic of Jupiter in the 707 day sidereal,
in my document defined in the Mars-Jupiter synodic section,
is [20] x [42] = [840] + "5 days not part of that period" to equal=[845MJ.
[840] / pentad [5]= [168]
and 845MJ / 5.................=[169]=....[13] x [13]

I think this means that Planet X also arrives during the 707 day sidereal,
perhaps not every one of the 707 sidereals that occurs,
but when Planet X comes to wreak havoc,
it is during the 707 day sidereal most likely,
and let's hope that this does not mean
that it slips right thru that Stargate Vector when it opens,
and it suddenly just shows up.

Now check this out.
Take the [16800] and apply the [5] , [12] , [13] to it like I did in my document,
to many sidereala and synodics

[16800] / Pentad[5] = [3360].............[3360] is our main man
...see my random proofs on the [336].

Apply the [19.5 / 18] degree angles

[1.0833333] x [3360]=.......[3640] or TEN EARTH LUNAR YEARS

Ha!

And remember that the Mars Jupiter synodic of [845]M J
applied to the Mars radius formula was
[.339745] x [845] M J / [26.5] = [10.8333]
and that is TEN Times the [19.5 / 18] degree angles
*************************************************


Hey,
I am just saying that this is all NOT COINCIDENCE and CHANCE,
as defined by our esteemed NASA scientists.  for Cydonia and the Pentad

NASA Geology
<img src="{SMILIES_PATH}/pennywise.gif" alt="Pennywise" title="pennywise" />
Wrong again.

The Grand Finale: Planet X Incoming

Planet X incoming.....[1310400]PX day sidereal

here it comes
[13] x [53] = [689]M sidereal in the ancient [13] heliosphere calendar
pentad [5] x [53] = [265]....[53] = [2 x 26.5]
Mars radius [.339745] x 780M= [265]

[1310400]PX / 689M= [1901.886792] x [26.5] = [50400]

...................[1310400]PX=................=[26] x [50400]

[26.5] x [26] = [689]M

[26.5 / 26]= [53 /52]= [265 / 260Tzolkin Earth calendar]

Planet X exists.

**************
Reply
#18
LOL
I bet that Planet X stuff went over the top eh?

I don't expect anyone to understand WHY the math works,
it just does,
because it is a calendar emanating from precise geometry
in the Pentad-12mouinds.

the point being that the way the numbers fall into place
so nice and evenly perfect is an indication that there is
a distinct mathematical system that is at play here,
emanating from the Pentad-Mars numerations.

These will be the last extrapolations I will attempt for awhile,
they kind of finish up Planet X.

On Planet X
one HAS TO USE tthe Lunar Earth Year of 364 days,
because it is a function of the [13]....x 28 days= [364]days
SEE MY DOCUMENT ON THIS

the 365.25 day Earth year does not work in the math.

Thus Planet X functions within the [13] heliospheric constant.
In days
............[13] x [100800]= [1310400]
So to quickly show how well the Planet X sidereal works:

My last post this number [16800] was achieved as such:

[X] x [Y] / [26.5]= [Z]
where X is the Mars radius and Y is the subject synodic or sidereal.
[Mars radius decimalized] x [ Planet X ] / 26.5= [Z]

[.339745] x [1310400]= [445201.848] / [26.5]degree angle= [16800]

NOW,
So [16800] / Pentad [5] =[3360].................................[3360]
Now Take
the orbit [sidereal] of Planet X at [1310400] / [39]=......[33600]
OR
[1310400]PX / 5pentad= [262080] / 780Msynodic=.......[336]

and [39] x [20] = 780M synodic is where my document began.

the other beauty of this 3600 year orbit of Nibiru in days,
as the function of the earth Lunar Year of [364]
is that the PX orbit vegisimalizes perfectly

[20] x [65520] = [1310400] PX days orbit
That [65520] does something grand, but that is pocket Aces for now.
-------------------------------------------------------------------------------

In my last post the PX math yielded this number.....[50400]
like this

[1310400] PX / 689M = [1901.886792] x [26.5] = [50400]
...................................[1310400] PX / [26]=......[50400]
[26.5] x [26] = [689]M
[26.5 / 26]= [53 /52]= [265 / 260Tzolkin Earth calendar]

Now take the orbit of Nibiru [1310400] / [260] Tzolkin calendar=
....................................................................[5040]

Interesting how the "numeric sets" repeat isn't it?
--------------------------------------------------------------

One last one for the road so to say

[1310400] PX / [13] = [100800]
[1310400] PX / [12]= [109200]................................[109200]

[100800] x [13/12] or the [19.5 / 18] degree angles= [109200]

[109200] / 780Mars synodic=.......... [140]
[109200] / [364] Earth Lunar Year = [300]
...................................[140] / [300]=..................[.4666666]

Now back to my original equation using the Tzolkin Mars radius
of [3397.45]
[.339745] x [364]Earth Lunar Year / [26.5]=...........[4.666686]

when the numeric sets match so close and repeat as evidence,
then this favors a valid Planet X.

<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
Reply
#19
Now that PX is over

I made one crucial edit in my first post.

This is why editing takes so long
on a huge document,
and typing fast .gets one in trouble,

In any case it is important because it defines
the synodic of Jupiter and Mars
from the Pentad pyramid.

I used a multiplication sign by accident
instead of a division sign,
and this happens when not editing all math tightly,

Revised in the post now:


SPECIAL NOTE

A multiplication sign was erroneously installed
instead of a division sign
in this equation
Sqrt. [2]= [1.4142].../ Sqrt [3] =[1.732]
.................[1.4142] / [1.732] =.........***[.8165]***
The synodic of Mars and Jupiter is.......[816.5] days,
all in a Pyramid developed from the Pentad tetrahedral grid pattern.

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Reply
#20
oops!

I sure didn't catch it.

Applause Applause Applause
On a satellite I ride. Nothing down below can hide.
Reply
#21
Hi Keith

I will do that in a few days then.
I am burning out and that typo error is an indication of that.

Please be sure that anyone that is verifying this document
and who reads the Final Random Pyramid Proof
knows that the typographcal error of the multiplicative sign
instead of the division sign is there **possibly** in the document
at the end in the Pentad Pyramid Proof.

I posted that in my last post,
and sent you a PM as well.

the Pentad Time Pyramid was added to my document the day
it was posted and was not fully edited,
as it was derived that morning and the night before
sending the document to you.

CAN ANYONE go into a pdf
and make one tiny edit
of that particular multiplication sign?
it is important and i do not know how to do that,
i cannot even open the pdf here on my computer.

I will have TWO new computers any day now,
and full Broadband access.


***ALSO VERY IMPORTANT***
the
***Planet X sidereal ALSO works with [365] day Earth year,***
the numbers ALL derive perfectly,

I used the Lunar Year [364], in my prior posts
because it allows the 13 to work perfectly in tandem

SO REVISED
[365]day earth Year x [3600] year PX orbit =[1314000]

vegisimal [20] x [65700]= [1314000]

This is the amended proof using the 365 day Earth year
and the [13] base Mars sidereal of [689]
[13] x [53] = 689
5 x [53] = [265]............[2 x [26.5]degree angle = [53]

365days x 3600 yearsPX= [1314000]

[1314000]PX / 689M=[1907.111756] x [26.5] = [50538.46154]

...................[1314000]PX=................=[26] x [50538.46154]

[26.5] x [26]= 689M
[26.5 / 26]= [53 /52]= [265 / 260Tzolkin Earth calendar]

---------------------------------------------------------

Revised for [365] Earth day from previous posts on PX

A number that kept popping up in my derivations
that I could not figure out was [0.4615384615]......rounded=[0.46154]

then I noticed that it is EXACTLY HALF
of the [19.5 / 18] degree angles = [.923077] rounded to 6 figures

So [.923077] divided by two =[0. 46154]...remember that

So I took the legendary sidereal of Planet X of 3600 years,
and to get the days of the sidereal I multiplied that by
[365] day Earth Year.

[365]days x [3600]years= [1,314,000] days....that is a lot of days,
THEN
I applied the Mars radius equation of mine to that,
[X] x [Y] / [26.5]= [Z]
where X is the Mars radius and Y is the subject synodic or sidereal.
[Mars radius decimalized] x [ Planet X ] / 26.5= [Z]

[.339745] x [1314000]= [446424.93] / [26.5]degree angle= [16846.2237]

ALSO [1314000] Planet X sidereal / 780M=.......................[1684.62]

Take the 845M J synodic of Mars -Jupiter during the 707 day sidereal

[1314000] / 845M J= [1555.029586]....x [19.5 / 18]degree angles=
.....................................................x [1.0833333]=............[1684.62]

hmm2.....what to do with that original number..............[16846.2237] ?

For some reason immediately I decided to divide it back by
the Earth Year of 365.

[16846.2237] / [365] =[46.154]......hmm2....holy shit look back up to the top! at my [19.5/18]angle halved
.................................[46.154]....to.....[0.46154]

[18 / 19.5] degree angle = [.923076923] / Pentad Pyramid EA length[2]=
.........................[.4615384615]
or rounded to 6 figures [.46154]

Now, I wonder if that is just coincidence...?


I think this means that Planet X also arrives during the 707 day sidereal,
perhaps not every one of the 707 sidereals that occurs,
but when Planet X comes to wreak havoc,
it is during the 707 day sidereal most likely,
and let's hope that this does not mean
that it slips right thru that Stargate Vector when it opens,
and it suddenly just shows up.

Now check this out.
Take the [16846.2237] and apply the [5] , [12] , [13]
to it like I did in my document,
to many sidereals and synodics

[16846.2237] / Pentad[5] = ........[3369.24474]

Apply the [19.5 / 18] degree angles

[1.0833333] x [3369.24474]=.......[3650] or TEN EARTH YEARS

Ha!
SEE Planet X works for [365] days as well !!!
----------------------------------------------------------

Further revised post using [365] days to get Planet X derivations



............[13] x [101076.9231]= [1314000] PX sidereal
So to quickly show how well the Planet X sidereal works:

My last edit this number [16846.2237] was achieved as such:

[X] x [Y] / [26.5]= [Z]
where X is the Mars radius and Y is the subject synodic or sidereal.
[Mars radius decimalized] x [ Planet X ] / 26.5= [Z]

[.339745] x [1314000]=[446424.93] / [26.5]degree angle= [16846.2237]

NOW,
So [16846.2237] / Pentad [5] =................................[3369.245]
Now Take
the orbit [sidereal] of Planet X at [131400] / [39]=......[33692.3]
OR
[1314000]PX / 5pentad= [262800] / 780Msynodic=.......[336.923]

and [39] x [20] = 780M synodic is where my document began.

the other beauty of this 3600 year orbit of Nibiru in days,
as the function of the earth Lunar Year of [364]
is that the PX orbit vegisimalizes perfectly

[20] x [65700] = [1314000] PX days orbit
That [65700] does something grand, but that is pocket Aces for now.
-------------------------------------------------------------------------------

In my last post the PX math yielded this number.....[50538.46154]
like this

[1314000]PX / 689M=[1907.111756] x [26.5] = [50538.46154]

...................[1314000]PX=................=[26] x [50538.46154]

[26.5] x [26] = [689]M
[26.5 / 26]= [53 /52]= [265 / 260Tzolkin Earth calendar]

Now take the orbit of Nibiru [1314000] / [260] Tzolkin calendar=
....................................................................[5053.846154]

Interesting how the "numeric sets" repeat isn't it?
--------------------------------------------------------------

At least that got cleared u
for PLANET X as well
and I have reached total math burnout,
taking a break
going shroom hunting today and tomorrow.

<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
Reply
#22
That's cool Vic.
when you get back it will all have perspective.

Rofl
On a satellite I ride. Nothing down below can hide.
Reply
#23
Quote:CAN ANYONE go into a pdf
and make one tiny edit
of that particular multiplication sign?
it is important and i do not know how to do that,
i cannot even open the pdf here on my computer.

OK V - done! It was page 90.

VS3_edit90.pdf

Had to extract image and text and paste into word, change and then
create new pdf page. The change has created a slightly different
page size for page 90!

Cheers
Reply
#24
Will do now.

<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
On a satellite I ride. Nothing down below can hide.
Reply
#25
<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
Reply
#26
Thanks guys,

my level of burnout is over the edge.

I will check the pdf when I can in a few days,
then condense a synopsis for Hoagland and anyone else.

I have not yet applied the "Codex" angles to the Planet X sidereal,
that will take time.

Tell DonAlgaerithms to not be a moron,
and learn to use his calculator.

He is just trying to play NASA Mole debunk skunk,
and he stinks.
like Phil Plait.

I am going to answer some of his questions later
once I read them.

<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />

off to the mountains
for the V
and my dad's B-day on the 27th

and the lunar eclipse is the 28th


Ha!
Reply
#27
Cheers <img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />

http://www.keithlaney.net/TheHiddenMess ... edit90.pdf
On a satellite I ride. Nothing down below can hide.
Reply
#28
Cheers
Reply
#29
This is just awesome, Vianova!

Just awesome...a little scary too, in a PX mind-boggling way ...

Congrats on your discovery.




Applause <img src="{SMILIES_PATH}/applause.gif" alt="Applause" title="applause" />

India
Reply
#30
Quote:Of course, the idea of hyperspace goes way back to Plato (427-347 B.C.), who suggested in his Cave allegory, that we are like prisoners of the 3-d world, identifying ourselves with our 3-d shadows, rather than the hyper-dimensional creatures we really are. Plato never used the word hyper-dimensional, but the idea is clearly in his story of the projection of the prisoner's shadows (a 2-d projection) on the cave wall. The prisoners because they are so securely chained, come to identify themselves with their shadows cast by a fire behind them; and they believe they, as shadows, are interacting with the shadows cast by people walking behind them. One of the prisoners breaks free of his chains and escapes to the world outside the cave, where he sees the full 3-d world. He can now really interact with the other 3-d people and objects. However, he goes back to try to rescue his former fellow prisoners. They mock him and challenge him to tell them what he thinks he sees in their shadow world. Because he has been in the bright sunlight outside the cave, his eyes- are not as keenly. adjusted to the dark shadow-world in which his fellow prisoners live. They can make out the details of the shadows better than he can. This proves to them that he is merely mad.

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Never invite a Yoda to a frog leg dinner.
Go ahead invite Yoda to a Frog leg dinner
Reply
#31
For reference below Pyramids,
and be sure to open the SPSR link for further below Pyramids
from their diagrams
[Image: 11sqrt2.jpg]


http://spsr.utsi.edu/articles/geometry/geometry.htm

all below that is my origination is
Copyright V. Showell 2007

FIRST,
I am not a math Houdini.
Dr P. is the math Houdini,
and he is the one that did the statistical analysis for SPSR,
that relegated the Pentad-12 mounds to NASA geology standards,
condemned to being "Chance and Coincidence",
literally dooming the site to geologic happenstance.

THIS IS WHY,
I did all the math that I have performed,
to attempt to rectify in some possible way,
all this Statistical Analysis by the SPSR PhD's
that relegate the Pentad to geologic "Chance and Coincidence".

Much of my work is great,
and certainly lots of it will be discarded as irrelevant.
I just put it all on the table,
and the debunkaholics and math science can rip it apart,
but what will stay on the table is certainly valid,
and a lot of my work will stand.


SO, I am back from the mountains doing what I WannaBe and WannaDo,
and that is Elvis Boletus hunting King Boletes!
Highly successful.

So I got back in town for an email from prominent PhD
that posts at SPSR,
who I sent my Pentad Time Pyramid,
and the three expansions of that pyramid to for review.

Now this kind of bugged Elvis Boletus a bit,
because he says,
where is your Sqrt[2] Pyramid?
and how does your Pyramid relate to the Pentad,
and how does the sqrt[5] fit in?

Well, a PhD knows better,
and the reason I have shown the 3 expansion pyramids earlier posts,
was to show how they all expand
FROM the Sqrt of [2],
and my Pentad EAlength=[2]Base Pyramid
has the sqrt[2] as all 4 lengths to the midpoint,
in the Pyramid Base,
so how could he miss that?
Dunno.

So I will now give you the Sqrt[2]Base pyramid,
which expands into the [2]base pyramid and so on.

In this pyramid I must find the sqrt[2]. sqrt[3], sqrt[5], sqrt[6]

[Image: sqrt2pyr.jpg]

As you can see the sqrt[3] becomes the SIDE ANGLE LENGTH,
and the base is sqrt[2]

NOW I need to find the Sqrt[5], sqrt[6]
and the [.8165] correlation to the Mars Jupiter Synodic.

Sqrt[6] = Side Angle Length / [.707107]= [2.44949]= Sqrt[6]
AND [.707107] is the Basesqrt[2] / in half as shown.

And of course the The Base length /  Side angle Length
Sqrt[2] / Sqrt[3]= [.8165] correlates to the mars Jupiter synodic
of 816.5 days.

ALL accounted for.

Now as for the direct SPSR diagrams of the Pentad-tetrahedral grid
I will finish the job.

Here is the SPSR link
refer to Diagram [4]
{how Sqrt[2] rectangle is related to Tetrahedron crossection}

http://spsr.utsi.edu/articles/geometry/geometry.htm

OK I need to replicate the sqrt[2], sqrt[3], sqrt]6]
***AND sqrt[5] for our SPSR guys,***
right from their own diagrams,
into Time Pyramids.

First is the Isoscles triangle from SPSR diagram [4]
then expanded into a pyramid base,
then into a Pentad Time Pyramid.

[Image: sqrt2McDPyrBase.jpg]

As you can see the sqrt[6] is right there with the sqrt[2] and sqrt[3]
in the Pyramid base,

Now the Pyramid itself

[Image: sqrt2McDPyramid.jpg]

And as you can see the Sqrt[5] is now the Side Face length,
and the Jupiter to Mars heliocentric alignment is preserved
right from SPSR diagrams.
Needless to say the the Sqrt[2] and sqrt[3] are right there as well,
and Sqrt[2] / Sqrt[3]= [.8165]
and the Sqrt[6] is the FULL DIAGONAL of the Pyramid base.


OK
now take the Sqrt[2] rectangle that the SPSR guys
are so stuck in 2-D with.
Let's create the same pyramid from the Sqrt[2] rectangle.

[Image: sqrt2rectanglePyrBase.jpg]

So expanding the Sqrt[2] rectangle into a pyramid
still yields both the Sqrt[5] and the Sqrt[6],
Sqrt[5]= Side face length
Sqrt[6] is the Full Pyramid base diagonal.
and the Sqrt[2] / Sqrt[3] still=s [.8165]

And that is all I have time for today

If anyone finds a mistake let me know,
and I will rectify.

NOW LOOK BELOW
AT MY 100Base Pyramid posted prior page
at the SIDE ANGLE LENGTH
I ROUNDED THAT OFF IN THE DIAGRAM
ACTAUL PRODUCT IS
[122.474481]
NOW look at the Sqrt[6] Diagonal length in the Pentad Time Pyramid
derived from the SPSR Diagram[4],
and notice the length to Pyramid Base midpoint
[1.22474481]
[122.474481].....numeric sets match !!!

Ha!

[Image: 11sqrt4.jpg]



<img src="{SMILIES_PATH}/cheers.gif" alt="Cheers" title="cheers" />
Reply
#32
Look at above post for diagrams to refer to.

For those interested,
I updated some of the Planet X stuff over in the other forum thread,
In the "Not 19.5" thread by Algorithnms,
where I have been exposing the history behind the scientist that performed
the statistical analysis for SPSR on the Pentad- 12 mounds.

Dr. P. also co-authored the space weapons propaganda booklet
that was recently published,
a literary work of distinct garbage IMO,
called Introduction to Planetary Defense....Alien Invasion..
and well beneath his capacities as an esteemed neocon astrophysicist,
but obviously contributed to as a funding focus for Defense -Energy sector
corporate gluttons to plunder further the NASA budget,
and line their pockets with NASA futures,
isolating priority missions in the search for life and artificiality,
both on Mars and elsewhere to the garbage can and all the hype on
the "Search for Life"
on other planets is a COVER STORY and a lie,
as they build the CEV for the Military Moon Base.

Dr. P. also was at the old GLP along with Phil Plait
partaking in debunk campaigns on astrophysics, physics,
general astronomy and especially debunking anything "conspiratorial"
in nature about Mars or Planet X.

Yet it was Dr. P. that performed the original Planet X derivations
in the 1980's, in which he actually assigned several different sizes,
masses and orbits of Planet X before he gave up. ,
though NAVY astronomer Harrington continued the work
by trying to go to New Zealand to search the southern skies for PX,
since that is the direction that PX "shows up out of nowhere" from,
and unfortunately he died in the process.

It makes one wonder as to wether the objective nature
of science and math
was applied to the statistical analysis performed by SPSR
that doomed the Cydonia site to "Geologic Chance and Coincidence",
but for now we will give them the benefit of the doubt,
because we don't need their stinking statistical analysis,
because WE ALL KNOW
that math science can statistically analyze any result it wishes to achieve,
including that we all only exist by sheer Chance and Coincidence.

That being said we return slowly to Planet X update.

First, the Mayan attribution from the Dresden Codex
on the sidereal of Mars
is 702 days.
I did not make this up,
it is FACT, and the PEER REVIEWED mathemeticians
that perfomed the study also analyzed a " possible 707 day average"
to the Mars sidereal.

If you read my document, I take that 707 day sidereal of Mars,
and work absolute magic with it,
confluencing with the [13] heliospheric calendar,
and literally prove that the standard western sidereal of Mars at 687 days,
and the Mayan 702 and 707 day sidereals BOTH exist,
and that Mars reaches a major geometric planetary alignment
with the inner planets, when it expands to that 707 day sidereal,
and that this may create the "Stargate" vector between the planets
and to the Pleiades.

these are the links to that math science analysis on the Mars sidereals
http://www.sciencenews.org/articles/200 ... thtrek.asp
http://www.pubmedcentral.nih.gov/articl ... rtid=29390


In the Pentad-12 mounds site were found a predominance of 4 angles
by SPSR research,
and these were [19.5] [26.5] [18] and [30] degrees.
If you have read my work.
you know what I accomplished using the [26.5] degree angle.

One of the big clues, that NO-ONE found in all their math analysis,
because they think flat and linear constrained by their own limitations,
was the squaring of the [26.5] degree angle,
and when squared it = [702.25]
directly correlating to the Mayan Calculative sidereal of 702 days.
This is not a coincidence.

The [19.5] squared yielded the Saturn synodic,
or specifically [19.5] is actually [19.47] in tehtrahedral geomotries,
and science uses 19.5 because it is close enough,
and [19.47] squared = 379, and the Saturn synodic is an AVERAGE at 378.

In the angles immediately one Codexes 19.5 x 30 degrees to equal the
Venus synodic of 585 days.
This is also accomplished in numeric set status as the [19.5] / [33.33333333],
both tetrahedral geometries, to equal [.585],
and though the Venus synodic is AVERAGED at 584,
the [13] calendar applies to the 585 as [13] x [45] = 585V.
AND
when you take the actual [19.47] / [33.3333333] you get exactly [.584]

So
on to Planet X,
and I will try and show a relationship with the Planet X orbit,
the Venus synodic to Earth and the Mayan calculative sidereal of 702days,
emanating from the Time Pyramids.

My first attempt at PX used the Earth Lunar Year,
because this aligned the [13] calendar,
and thus created beautiful derivations numerically,
and it is valid in that it would cover essentially 3590 years of PX orbit,
and using Mayan style calculations one would know at that point,
that in ten years PX will show up, if it didn't show up at that point.

So I will use the full 365.25 day Earth year now in calculations,
as I weave in the 585venus synodic
and the Mayan 702 day calculative sidereal.

Divide the 585V / 702M =[.833333333]
that number which is extensively analyzed in my document.

Now look at the Sqrt[2] rectangle base Pyramid that SPSR prof.
requested that I create, above posted in my thread here..

To attain the Side face length that revealed
the Mars-Jupiter heliocentric alignment,
one does simple geometry by squaring and adding up the triangle lengths
to attain the hypotenuse,
and that was [5] to be square rooted.
the FULL Diagonal of the sqrt[2] pyramid base is [6] to be square rooted.
[5] / [6] = [.8333333].
It is important to look both at the result as the square roots
AND the numerations that lead to those square roots
which become Side Face and Side Angle lengths etc.

Now in my Base100 Pyramid posted here above in this thread,
you take the SIDE FACE length [111.8034] square it=[12500]
and the SIDE ANGLE [122.474481] square it = [15000]
[12500/15000 = [.83333333]
and so we have two pyramids that express the ratio
of the 585Venus synodic to the Mars Mayan sidereal of 702 days.
PS in my Base100 pyramid I rounded the SIDE ANGLE Length to 122.475
and it is fully 122.474481]]

So we see that the 702 day Mayan sidereal of Mars is valid
exhibiting the [.8333333]
right from the SPSR sqrt[2] Base that I expanded into a pyramid.
Notice also in all the pyramids the numeration [.707107--rounded]
in various decimal placements,
and [.70710678] is EXACTLY half of the SQRT[2]
and that [.70710678] is corrrelative DIRECTLY to the 707 day
"average Mars sidereal" shown in the links I have supplied you with above,
by numeric set process of decimal variation.

This is shown in my document in the very first but simple
Pentad 5 by 5 by 7.07 base Pyramid
and
sin 45 degrees= [.707]
cos 45 degrees =[.707]
tan = [1]
and these supply the perfect triangle to develop the Pyramid base.
{see document}

Planet X has a legendary 3600 year orbit......[60 x 60]
............................................................[13] x [60]=780Msynodic

[3600] x [365.25] days per year = [1314900] days PX sidereal.

Now "Codex" in the 12 mounds angle of [19.5] degrees.

[19.5] x [1314900] PX = [25640550]
Now divide that by the Mayan calculative sidereal of [702] days

[25640550] / [702]M =[36525].......recognize that number?
that is EXACTLY 100 Earth Years of [365.25] days..

THAT is not coincidence......Cheers for Planet X

TEN [19.5] degree angles in the mounds from SPSR analysis.

[19.5] x [1314900] PX = [25640550]
Now divide that by the Mayan calculative sidereal of [702] days

[25640550] / [702]M =[36525].......recognize that number?
that is EXACTLY 100 Earth Years of [365.25] days..

<img src="{SMILIES_PATH}/smoke.gif" alt="Smoke" title="smoke" />
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#33
I am in the process of a final edit.

So before I post more on the pyramids,

I wanted to do a followup
on Planet X
and the angles in the Pentad--12 mounds at Cydonia.

This does not mesn that Planet X exists,
but it does mean that IF it exists,
the Planet X will fit right into the heliosphere like a
Time Surfing Tuning Fork.

Legendary Planet X sidereal of 3600 years

EY is Earth Year

Angles in the Mounds

[19.5] [26.5] [18] and [30] degrees angles predominate

Earth Year of [365.25] days x 3600 years = [1314900] PX days

[1314900] PX x [19.5] angle = [25640550] / 702 Mayan Mars sidereal =
[36525] or 100 Earth years exact


[1314900] PX x [19.5] angle =[25640550] .../ [18] angle = [14224475]
..................................[14224475] / [365.25] EY = [3900]
numeric set of 3900 is [39]....39 x 20 = 780 mars synodial to Earth

OR
1314900 x [18] degree angle =[23668200] / [365.25] EY= [64800]
numeric set [648] corresponds to the Jupiter and Mars ellipticities
Mars[.00648], Jupiter[.0648]


[1314900]PX x [30] angle = [39447000] / [365.25]EY = [108000]
numeric set [108]...108 dgrees in the pentagon angles,
Mayans have the [108] dimensions


[1314900] PX [19.5]angle =[25640550].../ [30] angle = [854685]
................................................[854685] / [365.25] EY = [2340]
2340 / 780M = 3......Tzolkin Mayan calendar[260] x [3] = 780M synodial



and l;ast but not least Omkulkancotal Codex this one

[1314900] PX x [19.5] = =[25640550]..../ [26.5] angle =[967567.9245]
................=[967567.9245] / [365.25] EY = [2649.056604]
...........................................100 x [26.5] = [2650]


[1314900] x [26.5] degree angle = [34844850].../ [365.25] EY =[95400]
now take my [52/ 53] ratio in my document
of the Mars-Earth year to week ratio....
[95400] x [52/53] = [93600]...
[936] the perfect numeric set pentagonal pyramidal number

[93600] / 780 Mars synodial = [120] or Ten times the twleve mounds
12 x 78 = 936
10 x 78 = 780 Mars synodial to earth

780 / 936 = [.8333333] the V2 cosmic heliosphere constant

Yes I know it is odd boring math,
but the Planet X orbital period of [1314900] days WORKS
with the Mars Pentad-12 mounds angles !


***
Now to consider that if Planet X is a brown dwarf with a "planet x",
and it according to one site...
comes into the solar sytem between Mars and Jupiter
outside the asteroid belt....at a 30 degree angle,
and if such brown dwarf exists as a massive gravitational influence,
it might just pull Mars
out of it's standard 687 day sidereal
to the unusual geometric pyramidal planetary alignment,
that would then create the Mars 707 day sidereal,
and the 53 week earth year,
which creates the [13] Calendar planetary magic.

Dunno.

So how long would PX be in the inner solar system passing though?

Ten years is my guess.
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